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12t^2+72t+60=0
a = 12; b = 72; c = +60;
Δ = b2-4ac
Δ = 722-4·12·60
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-48}{2*12}=\frac{-120}{24} =-5 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+48}{2*12}=\frac{-24}{24} =-1 $
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